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Show that `12^n` cannot end with the digits `0` or `5` for any natural number `n`

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Show that `12^n` cannot end with the digits `0` or `5` for any natural number `n`
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`:. 12=2xx2xx3=2^(2)xx3`
`implies 12^(n)=(2^(2)xx3)^(n)=2^(2n)xx3^(n)`
`:.` it has no term containing 5. ltbr. `:.` no vaule of n `in ` N for which `12^(n)` ends with digit 0 or 5. Hence Proved.
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