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In triangle ABC, P is midpoint of AB and Q is midpoint of AC. If AB=9.6cm, B=11 cm and AC=11.2 cm. The perimeter of trapezium PBCQ is:

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As `P` is the mid point of `AB`,
`:. PB = 1/2(AB) = 9.6/2 = 4.8cm`
As `Q` is the mid point of `AC`,
`:. CQ = 1/2(AC) = 11.2/2 = 5.6cm`
Also, `PQ` will be parallel to `BC` from the mid point theorem.
`:. PQ = 1/2(BC) = 11/2 = 5.5cm`
`:.` Parimeter of trapezium ` = PB+BC+CQ+PQ = 4.8+5.6+5.5+11 = 26.9cm`

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