Question

Find the HCF of 96 and 404 by the prime factorisation method. Hence, find their LCM.

Answer 1

Here, `a = 96 = 16**6 = 2^5**3^1`
`b = 404 = 4**101 = 2^2**101^1`
So, HCF will be the common factor with their least power.
In this case, common factor is ` 2` and its least power is ` 2`.
So, `HCF = 2^2 = 4`
As, we know,
`a**b = HCF**LCM`
`LCM = (a**b)/(HCF) = (96**404)/4 = 9696`