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+1 vote
1.9k views
in Derivatives by (49.4k points)
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The maximum value of (log x/x) is

A. (1/e)

B. 2/e

C. e

D. 1

1 Answer

+2 votes
by (50.9k points)
selected by
 
Best answer

Answer is : A. (1/e)

⇒ f’(x) = log x – 1

⇒ Put f’(x) = 0

We get x = e

F’’(x) = 1/x

Put x = e in f’’(X)

1/e is point of maxima

∴ The max value is 1/e.

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