Question

Assuming earth to be a perfect sphere of radius 6400 km. The value of acceleration due to gravity changes by what value from poles to equator for a period of 1 day?

(a) 3.5 x 10^-2 ms^-2

(b) 3.38 x 10^-2 ms^-2

(c) 3 x 10^-2 ms^-2

(d) 2.25 x 10^-2 ms^-2

Answer 1

Correct option: (b) 3.38 x 10^-2 ms^-2

Given, R = 6400 km = 6.4 x 10⁶ m

T = 1day = 24 x 60 x 60 x 8.64 x 10⁴ s

The value of g with latitude is