Question

A capacitor of capacitance 2 µF is charged by connecting a battery of 100 V across its plates. Now, battery is disconnected and another capacitor of capacitance 6 µF is connected in parallel to first capacitor. Then, the ratio of total energy stored by both capacitors to initial energy of first capacitor is

(a) 2/3

(b) 3/4

(c) 1/4

(d) 1/2

Answer 1

Correct option is (c) 1/4

Initial energy of first capacitor,

When both capacitors are connected in parallel, then equivalence capacitance

C = C₁ + C₂

= 2 + 6 = 8 μF

Now, potential across each capacitor

Therefore, final total stored energy