Question

If the temperature of the sink of a Carnot engine is 57°C and its efficiency is 10%, then the temperature of the source is

(a) 227°C

(b) 93.6°C

(c) 127.5°C

(d) 85.7°C

Answer 1

Correct option is (b) 93.6°C

Answer 2

efficiency=T2-T1/T2                                                                                                                       T2=temperature of source    T1=temperature of sink                                                                            so,      0.1=T2-330k/T2   (K IS KELVIN)                                                                                                  T2=366.6k                                                                                                                                     T2=93.6 C