Question

Calculate the work done by a gas as it is taken from 1 to 2, 2 to 3, and 3 to 1 as shown in the figure. The work done in cyclic process 1 → 2 → 3 → is

(a) p₀V₀

(b) 2 p₀ V₀

(c) -2 p₀ V₀

(d) - p₀ V₀

Answer 1

Correct option: (d) - p₀ V₀

ΔW_{1 → 2 → 3 → 1} = Area of 1 → 2 → 3

= - \(\cfrac{1}{2}\) (2 p₀ - p₀)(3V₀ - V₀) = - p₀V₀