Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.4k views
in Chemistry by (37.1k points)
closed by

Solubility of CaCl2 in term of solubility product (Ksp) can be given as:

(a) (Ksp)1/3

(b) \(\left(\cfrac{K_{sp}}{2}\right)^{1/3}\)

(c) \(\left(\cfrac{K_{sp}}{4}\right)^{1/3}\)

(d) \(\left(\cfrac{K_{sp}}{2}\right)^{1/2}\)

1 Answer

+1 vote
by (35.1k points)
selected by
 
Best answer

Correct option:  (c) \(\left(\cfrac{K_{sp}}{4}\right)^{1/3}\)

For the reaction,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...