Given :
Equation of plane : 2x – 3y + 6z + 21 = 0
To Find :
Length of perpendicular drawn from origin to the plane = d
Formulae :
1) Distance of the plane from the origin :
Distance of the plane from the origin is given by,
d = \(\frac{p}{|\bar{n}|}\)
Answer :
For the given equation of plane
2x – 3y + 6z = -21
Direction ratios of normal vector are (2, -3, 6)
Therefore, equation of normal vector is

From given equation of plane,
p = -21
Now, distance of the plane from the origin is
