∫ e^x {tan^-1 x + 1/(1 + x^2)} dx = ?

Question

Mark (√) against the correct answer of the following:

\(∫ e^x \left\{tan^{-1}x + \frac{1}{(1 + x^2)}\right\} dx = ?\)

∫ e^x {tan^-1x + 1/(1 + x²)} dx = ?

A. e^x . \(\frac{1}{(1 + x^2)}+C\)

B. e^x tan^-1 x + C

C. - e^x cot^-1 x + C

D. None of these

Answer 1

Correct answer is B.

∫ e^x {tan^-1x + 1/(1 + x²)} dx

Formula used: