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Plot a graph showing the variation of coulomb force (F) versus \(\left(\cfrac{1}{r^2}\right)\), where r is the distance between the two charges of each pair of charges: (1 µC, 2 µC) and (2 µC, – 3 µC). Interpret the graphs obtained.

F=\(\cfrac{1}{4\pi\varepsilon_0}\cfrac{q_1q_2}{r^2}\)

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The graph between F and \(\cfrac1{r^2}\) is a straight line of slope \(\cfrac{1}{4\pi\varepsilon_0}\)q1q2 passing through

Since, magnitude of the slope is more for attraction, therefore, attractive force is greater than repulsive force.

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