Let l be the balance length of the segment AX on the potentiometer wire for given resistance R and S.
(a) If resistance R is increased, the current flow in the main circuit (or wire AB) will
decrease. From relation K = \(\frac{pI}{L}\) the potential gradient along the wire AB will decrease.
To balance the emf of the cell, the point X will shift toward the point B, i.e.,
ε = kl = k′l′
If k′ < k, so l′ > l
(b) For the given resistance R, the potential gradient along the wire remain same. Balance length ‘l’ remain constant. ε = kl
And no current flows in the resistance S. If resistance S is increased/decreased there is no change in the balance length.