Question

A test charge ‘q’ is moved without acceleration from A to C along the path from A to B and then from B to C in electric field E as shown in the figure.

(i) Calculate the potential difference between A and C.

(ii) At which point (of the two) is the electric potential more and why?

Answer 1

(i) Since electric field is conservative in nature, the amount of work done will depend upon initial and final positions only.

(ii) V_C > V_A, because direction of electric field is in decreasing potential.