Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.5k views
in Chemistry by (33.8k points)
closed by

Calculate the number of atoms present per unit cell in: 

i. Simple or primitive cubic lattice

ii. Body-centred cubic lattice

iii. Face-centred cubic lattice

2 Answers

+1 vote
by (34.3k points)
selected by
 
Best answer

i. Simple or primitive cubic lattice:

a. In simple cubic unit cell, eight constituent particles (spheres) are present at eight corners of unit cell. 

b. Unit cells repeat in three dimensions to form the complete crystal. The constituent particles at the corners are shared by neighbouring unit cells. 

c. A constituent particle present at a corner is shared by eight neighbouring unit cells. Its contribution to a unit cell is only 1/8.

d. Thus, the number of atoms present in each unit cell = 8 corner atoms \(\times\) \(\cfrac{1}{8}\) atom per unit cell = 1

Thus, simple cubic lattice has one atom per unit cell.

ii. Body-centred cubic lattice (bcc):

a. In body-centred cubic unit cell, eight constituent particles (spheres) are present at eight corners of unit cell. One constituent particle is present at the centre of the body of the unit cell.

b. A constituent particle present at a corner is shared by eight neighbouring unit cells. Its contribution to a unit cell is only 1/8.

Thus, the number of atoms present at the corners per unit cell

= 8 corner atoms \(\times\cfrac{1}{8}\) atom per unit cell = 1

c. The constituent particle present at the centre of the body of the unit cell is not shared by any other unit cell. Its contribution to a unit cell is l.

Thus, the number of atoms present at the centre of the cube = 1

d. The total number of atoms present in the unit cell = 1 + 1 = 2

Thus, body centred cubic has 2 atoms per unit cell.

Note: When layers of constituent particles are superimposed on one another, a simple cubic structure is formed. To form a body centred cubic structure, second layer of constituent particles is fitted on the depressions of the first layer and the third layer is fitted on the depressions of the second layer. Each sphere is in contact with eight spheres. Four spheres are present in the layer above and four spheres are present in the layer below. Thus, the coordination number of the constituent particle in body-centred cubic lattice is eight.

iii. Face-centred cubic lattice (fcc):

a. In face-centred cubic unit cell, eight constituent particles (spheres) are present at eight corners of unit cell. Six constituent particles (spheres) are present at centres of six faces. 

b. A constituent particle present at a corner is shared by eight neighbouring unit cells. Its contribution to a unit cell is only 1/8.

Thus, the number of atoms present at corners per unit cell

= 8 corner atoms \(\times\cfrac{1}{8}\)atom per unit cell = 1

c. A constituent particle present at the centre of a face is shared by two neighbouring unit cells. Its contribution to a unit cell is only 1/2.

The number of atoms present at faces per unit cell = 6 atoms at the faces \(\times\cfrac{1}{2}\) atom per unit cell = 3

d. The total number of atoms per unit cell = 1 + 3 = 4

Thus, a face centred cubic unit cell has 4 atoms per unit cell.

Note: The coordination number of the constituent particle in a cubic close-packed structure or face centred cubic lattice is twelve i.e., four spheres are present in the layer above, four spheres in the layer below and four spheres in the layer of the constituent particle.

0 votes
by (398 points)

Simple Or Primitive Cubic Lattice

  • The atoms in the primitive cubic unit cell are present only at the corners
  • Every atom at the corner is shared among eight adjacent unit cells
  • In each cubic unit cell, there are 8 atoms at the corners. Therefore, the total number of atoms in one unit cell is

    8 × 1/8 = 1 atom.

    Body-Centered Cubic Lattice

  • In BCC unit cell every corner has atoms.
  • There is one atom present at the center of the structure
  • 8 corners × 1/8 per corner atom = 8 × 1/8 = 1 atom
  • 1 body centre atom = 1 × 1 = 1 atom
  • Therefore, the total number of atoms present per unit cell = 2 atoms

Face-centred Cubic lattice

  • In the FCC unit cell atoms are present in all the corners of the crystal lattice
  • Also, there is an atom present at the center of every face of the cube
  • 8 corners × 1/8 per corner atom = 8 × 1/8 = 1 atom
  • 6 face-centered atoms × 1/2 atom per unit cell = 3 atoms
  • Therefore, the total number of atoms in a unit cell = 4 atoms.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...