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in Laws of motion by (15.4k points)
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Blocks A and B in Figure are connected by a bar of negligible weight. If mass of A and M are 170 kg each and  µA = 0.2 and µB = 0.4 , where µA and µB are the coefficients of limiting friction between blocks and plane, calculate the force in the bar. (g = 10 m/s2)

(A) 150 N 

(B) 75 N 

(C) 200 N 

(D) 250 N

2 Answers

+1 vote
by (39.4k points)
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Best answer

Correct option is (A) 150 N

Here both the particles are constrained to move together.

Hence aA = aB Now let us first find the net force down the incline;

i.e (m1 + m2)g sin θ

i.e. force in the bar is 150 N.

+1 vote
by (15.9k points)

correct answer is (A)  150 N

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