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0 votes
4.3k views
in Laws of motion by (15.4k points)
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In the arrangement shown in the Figure pulley is smooth and massless and string is light. Friction coefficient between A and B is µ. Friction is absent between A and plane. Select the correct alternative(s)

(A) acceleration of the system is zero if \(\mu \ge \frac{m_B - m_A}{2m_B}\) tan\(\theta\) and mB > mA

(B) Force of friction between A and B is zero if mA = mB

(C) B moves upwards if mB < mA

(D) Tension in the string is mg (sin θ−µ cosθ) if mA = mB = mC

2 Answers

+1 vote
by (39.0k points)
selected by
 
Best answer

Correct options are (A) and (B)

Tension itself balances both the masses.

So, no necessity for any friction.

C: we cannot explicitly say that.

We need more information on µ.

D: when mA = mB;

Put friction f = 0 in (i) and (iii)

And subtract them to get Tension ‘T’.

+1 vote
by (15.9k points)

Correct answer is 

(A) acceleration of the system is zero if \(\mu \ge \frac{m_B - m_A}{2m_B}\) tan\(\theta\) and mB > mA

(B) Force of friction between A and B is zero if mA = mB

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