Let p : The Switch S1 is closed.
q : The Switch S2 is closed.
\(\sim\)p : The Switch\(S'_2\) is closed or the switch S1 is open.
\(\sim\)q : The switch \(S'_2\) is closed or the switch S2 is open
The symbolic form of the given circuit is:
(p\(\lor\)q) \(\land\) (\(\sim\)p) \(\land\) (\(\sim\)q)
In the above truth table, all the entries in the last column are ‘F’,
\(\therefore\)the given circuit represents a contradiction.
\(\therefore\) Irrespective of whether the switches S1 and S2
are open or closed, the given circuit will
always be open (i.e. off).
