Question

A solenoid of length 1.0 m, radius 1 cm and total turns 1000 wound on it, carries a current of 5 A. Calculate the magnitude of the axial magnetic field inside the solenoid. If an electron was to move with a speed of 10⁴ ms^–1 along the axis of this current carrying solenoid, what would be the force experienced by this electron?

Answer 1

Magnetic field inside a solenoid,

B = μ₀nI

I = 5A

∴ B = (4π x 10^-7) x 1000 x 5

= 20 x 3.14 x 10^-4 J = 6.28 x 10^-3 T, along the axis

Force experienced by electron

F_m = qvB sin θ

Here q = - e,v = 10⁴ m/s,

θ = angle between \(\overrightarrow{v}\) and \(\overrightarrow{B}\) = 0

∴ F_m = - evB sin 0° = 0 (Zero)