Question

The amount of Ag (atomic mass = 108) deposited at the cathode when a current of 0.5 amp is passed through a solution of AgNO₃ for 1 h is closest to

(a) 2 g

(b) 5 g

(c) 108 g

(d) 11 g

Answer 1

Answer is : (a) 2 g

Given, current, I = 0.5 A

Time, t = 1 hr = 3600 s

According to Faraday’s IInd law of electrolysis,

W = Atomic mass x I x t/96500 = 108/96500 x 0.5 x 36000 = 2 g