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If a cycle wheel of radius 0.4 m completes one revolution in one second, then acceleration of the cycle is

(A) 0.4 π m/s2 

(B) 0.8 π m/s2 

(C) 0.4π2m/s2 

(D) 1.6π2 m/s2

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Answer is (D) 1.6π2 m/s2

Using,

ω = 2πn = 2π x 1 = 2π rad/s

a = rω2 = 0.4 x (2π)2 = 0.4 x 4 π2 

a = 1.6 π2 m/s2

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