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An aircraft executes a horizontal loop with a speed of 150 m/s with its wings banked at an angle of 12° The radius of the loop is (g = 10 m/s2)

(A) 10.6 km 

(B) 9.6 km 

(C) 7.4 km 

(D) 5.8 km

1 Answer

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Answer is (A) 10.6 km

Using, tan θ = \(\frac{v^2}{rg}\)

∴ tan 12° = \(\frac{(150)^2}{r\times10}\)

∴ r = 10.6 x 103m = 10.6 km

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