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Show that, log [√(x^2+1)+x]+log[√(x^2+1-x)]=0.

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Show that,

log [√(x2+1)+x]+log[√(x2+1-x)]=0.

\(log\left[\sqrt{x^2+1}+x\right]+ log\left[\sqrt{x^2+1}-x\right]=0\).

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1 Answer

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L.H.S. = \(log\left[\sqrt{x^2+1}+x\right]+ log\left[\sqrt{x^2+1}-x\right]=0\)

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