Given, area of a circle = 88.2 sq.m, \(\pi\) = 3.142
But, area of a circle = \(\pi\)r2
\(\therefore\) 88.2 = 3.142 \(\times\) r2
Taking log on both sides, we get
log10 88.2 = log10 3.142 + log10 r2
= log10 3.142 + 2 log10 r
\(\therefore\) 2 log10 r = log10 88.2 - log10 3.142
= 1.9455 - 0.4972 = 1.4483
\(\therefore\) log10 r = 0.72415 = 0.7242
\(\therefore\) r = antilog (0.7242) = 5.299 = 5.30 m