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Class 7 Maths MCQ Questions for Perimeter and Area with Answers?

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Students can get to the Class 7 Maths MCQ Questions for Perimeter and Area with Answers dependent on the new exam Pattern. It assists your test preparation and you can get a decent hold on the chapter. Use MCQ Questions for Class 7 Maths with Answers during exam preparation and score the maximum marks in the test. 

Understudies can access the Class 7 MCQ Questions of Perimeter and Area with Answers from here and test their critical problem-solving abilities. Clear every one of the essentials and plan altogether for the test-taking assistance from Class 7 Maths Perimeter and Area Objective Questions. Learn various MCQ Questions of Perimeter and Area Class 7 with answers gave itemized arrangements by looking beneath.

Practice MCQ Questions for Class 7 Maths

1. Perimeter of a square

(a) side × side
(b) 3 × side
(c) 4 × side
(d) 2 × side

2. The perimeter of a rectangle whose length(l) and breadth(b) are given, is

(a) 2(l+b)
(b) 2l+b
(c) 2l+3b
(d) None of these

3. Area of a square

(a) side × side
(b) 2 × side
(c) 3 × side
(d) 4 × side

4. Area of a rectangle of length l and breadth b is

(a) l × b
(b) l + b
(c) 2 × (l + b)
(d) 6 × (l + b)

5. Area of a triangle

(а) base × height
(b) 1/2 × base × height
(c) 1/3 × base × height
(d) 1/4 × base × height

6. The area of a square plot is 1600 m2. The side of the plot is

(a) 40 m
(b) 80 m
(c) 120 m
(d) 160 m

7. The area of a square is 121 m2. Its side is

(a) 11 m
(b) 21 m
(c) 31 m
(d) 41 m

8. The area of a rectangular field is 250 m2. If the breadth of the field is 10 m, find its length.

(a) 25 m
(b) 50 m
(c) 100 m
(d) 125 m

9. The perimeter of a rectangle is 30 m. Its length is 10 m. Its breadth is

(a) 5 m
(b) 10 m
(c) 15 m
(d) 3 m

10. The perimeter of a square is 48 cm. Its area is

(a) 144 cm2
(b) 12 cm2
(c) 48 cm2
(d) 100 cm2

11. The area of a rectangular room is 150 m2. If its breadth is 10 m, then find its length.

(a) 15 m
(b) 25 m
(c) 50 m
(d) 55 m

12. A rectangular wire of length 40 cm and breadth 20 cm is bent in the shape of a square. The side of the square is

(a) 10 cm
(b) 20 cm
(c) 30 cm
(d) 40 cm

13. The area of a parallelogram of base 5 cm and height 3.2 cm is

(a) 8 cm2
(b) 12 cm2
(c) 16 cm2
(d) 20 cm2

14. The area of the parallelogram ABCD in which AB = 6.2 cm and the perpendicular from C on AB is 5 cm is

(a) 30 cm2
(b) 29 cm2
(c) 28 cm2
(d) 31 cm2

15.  One of the sides and the corresponding height of a parallelogram are 3 cm and 1 cm respectively. The area of the parallelogram is

(a) 1 cm2
(b) 3 cm2
(c) 6cm2
(d) 12 cm2

16. If the area of a parallelogram is 16 cm2 and the base is 8 cm, find the height.

(a) 1 cm
(b) 2 cm
(c) 3 cm
(d) 4 cm

17. The area of a parallelogram is 20 cm2 and the height is 2 cm. Find the corresponding base.

(a) 3 cm
(b) 4 cm
(c) 5 cm
(d) 2.4 cm

18. Find the area of ∆ ABC

(a) 3 cm2
(b) 4 cm2
(c) 6 cm2
(d) 12 cm2

19. The radius of a circle is 7 cm. Its circumference is

(a) 22 cm
(b) 44 cm
(c) 11 cm
(d) 66cm

20. The diameter of a circle is 14 cm. Find its circumference

(a) 14 cm
(b) 24 cm
(c) 44 cm
(d) 66 cm

21. The radius of a circle is 7 cm. Find its area

(a) 154 cm2
(b) 77 cm2
(c) 11 cm2
(d) 22 cm2

22. When the circumference and area of a circle are numerically equal, what is the diameter numerically equal to?

(a) Area
(b) Circumference
(c) 271
(d) 4

23. Find the area of a verandah 2.25 m wide constructed outside a room 5.5 m long and 4 m wide.

(a) 36sq.m
(b) 63sq.m
(c) 64sq.m
(d) 84sq.m

24. The area of a circle is 2464m2 , then the diameter is

(a) 56 m
(b) 154 m
(c) 176 m
(d) none of these

25. The area of a circle is 2464m2 , then the diameter is

(a) Two
(b) Four
(c) One-half
(d) One-quarter

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Answer

1. Answer: (c) 4 × side

Explanation: Side+Side+Side+Side. Now, as we know, the length of all the four sides of a square are equal so the perimeter is four times the length of any side of a square. The perimeter of a square = 4 x sides.

2. Answer: (a) 2(l+b)

Explanation: Perimeter of a rectangle is the sum of all its four sides.Since, two sides measure l and the other two sides measure b , Perimeter of a rectangle whose length(l) and breadth(b) are given, is l+b+l+b=2(l+b).

3. Answer: (a) side × side

Explanation: Area =a²

Where, A = Area of Square, a = Side of the square

4. Answer: (a) l × b

Explanation: The area of a rectangle with length l and breadth b is given by A=l×b

5. Answer: (b) 1/2 × base × height

Explanation: The area A of a triangle is given by the formula A=1/2bh where b is the base and h is the height of the triangle.

6. Answer: (a) 40 m

Explanation: Side = \(\sqrt{1600 }\)

= 40 m

7.Answer: (a) 11 m

Explanation:  Side = \(\sqrt{121}\)

= 11 m

8. Answer: (a) 25 m

Explanation: Length = 250/10

= 25 m

9. Answer: (a) 5 m

Explanation: 30 = 2 (Length + Breadth)

⇒ 30 = 2 (10 + Breadth)

⇒ Breadth = 5 m

10. Answer: (a) 144 cm2

Explanation: Side = 48/4 

= 12 cm

∴ Area = 12 × 12 = 144 cm2

11.Answer:: (a) 15 m

Explanation:  Length = 150/10 

= 15 m

12.Answer:: (c) 30 cm

Explanation:  Side of square = \(\frac{2(40+20)}{4}\)

= 30 cm

13.Answer:: (c) 16 cm2

Explanation:  Area = 5 × 3.2 

= 16 cm2

14. Answer: (d) 31 cm2

Explanation:  Area = 6.2 × 5 

= 31 cm2

15. Answer: (b) 3 cm2

Explanation:  Area = 3 × 1 

= 3 cm2

16. Answer:(b) 2 cm

Explanation:  Height = 16/8 

= 2 cm

17.Answer: (d) 2.4 cm

Explanation: Base = 20/2 

= 10 cm

18.Answer:: (c) 6 cm2

Explanation: Area = \(\frac{4\times3}{2}\)

= 6 cm2

19. Answer: (b) 44 cm

Explanation: Circumference = \(2\times\frac{22}{7}\times 7\)

= 44 cm

20.Answer: (c) 44 cm

Explanation: Circumference = \(\frac{22}{7}\times 7\)

= 44 cm

21.Answer: (a) 154 cm2

Explanation: Area = \(\pi r^2\)

\(\frac{22}{7}\times7\times7\)

= 154 cm2

22. Answer: (d) 4

Explanation: Circumference of circle = Area of circle

\(2\pi r=\pi r^2\)

\(d=(\frac{d}{2})^2\)

4d = d2

⇒d = 4

23. Answer: (b) 63sq.m

Explanation: Length of room =5.5m, 

Width of room = 4m, 

Width of verandah which is constructed all along outside of room = 2.25m, 

Cost of cementing of verandha = Rs 200 per sq.m

∴, Length of room with verandah = 5.5+2.25+2.25 =10m

Width of room with verandah = 4+2.25+2.25 = 8.5m

Area of room = Length×Width = 5.5×4 = 22m2
 
Area of room with verandah = Length×Width = 10×8.5 = 85m2
 
Area of verandah = Area of room with verandah−Area of room

=85−22

= 63m2

24. Answer: (a) 56 m

Explanation: By given, Area = 2464m2

\(\frac{\pi d^2}{4}=2464\)

\(d^2=\frac{2464\times4}{\frac{22}{7}}\)

= 3136

d = \(\sqrt{3136}\) = 56m

25. Answer: (c) One-half

Explanation: The area of circle whose radius is r = πr2

And area of semi circle whose radius is r = \(\frac{\pi r^2}{2}\)

Then ratio of area of semi circle to the  area of circle = \(\frac{\pi r^2}{\frac{\pi r^2}{2}}=\frac{1}{2}.\)

The area of the semi-circle is one-half of area of circle.

Click here for Practice MCQ Questions for Perimeter and Area Class 7

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