Correct option: (C) 1.344 x 1018
22.4 L of water contains NA molecules
22400 mL of water contains NA molecules
1 mL of water i.e., 20 drops contains
\(\cfrac{N_A}{22400} \) molecules
∴ 1 drop contains \(\cfrac{N_A}{22400\, \times 20} \) = \(\cfrac{6.022\, \times\, 10^{23}}{448\, \times 10^3} \)
= 1.344 x 1018