\(\frac{11}{8},\frac{14}{8},\frac{17}{8},... \) a = \(\frac{11}{8}, \,d=\frac{14}{8}-\frac{11}{8}=\frac{3}{8}\)
Algebric expression = xn = dn + (f - d)
= \(\frac{3}{8}n+(\frac{11}{8}-\frac{3}{8})=\frac{3}{8}n+1\)
If ‘n’ is a multiple of 8 then 4, 7, 10, … is a sequence having whole numbers
Common difference = 3,This is an arithmetic sequence.
