a. Total numbers in each sequence can be written as
1, 3, 5, …. xn = 2n – 1
Numbers in the 30th row = 2 x 30 – 1 = 59
b. Last number in the first row = 12 = 1
Last number in the second row = 22 = 4
Last number in the third row = 32 = 9
Last number in thew 30th row = 302 = 900
c. Number of terms in the 30th row = 59
Last number in the 30th row = 900
First number in the 30th row + 58d = Last term in the 30th row
First number in the 30th row + 58 x 1 = 900 First
number in the 30th row = 900 – 58 = 842
d. The sum of all terms in the first 30 rows = \(\frac{900\times901}{2}\)
= 450 × 901 = 405540
Arithmetic Sequences Memory Map
![](https://www.sarthaks.com/?qa=blob&qa_blobid=5942251379993332336)