Question

In the figure given below, ABCD is a square of side 14 cm with E, F, G and H as the mid points of sides AB, BC, CD and DA respectively. The area of the shaded portion is

(a) 44cm²

(b) 49 cm²

(c) 98 cm²

(d) 49π/2 cm²

Answer 1

Correct answer is: (c) 98 cm²

Shaded area = Area of semicircle + (Area of half square – Area of two quadrants)

= Area of semicircle +(Area of half square – Area of semicircle) = Area of half square

= 1/2 \(\times\) 14 \(\times\) 14 = 98 cm²