Question

Corollaries of inscribed angle theorem `:`
Angle inscribed in the same arc arc contruent
Given `:` (1) A circle with centre O
(2) `/_ABD` and `/_ACD ` are inscribed in arc ABC and intercepts arc APD.
To prove `:` `/_ABD ~= /_ACD `

Answer 1

Proof `:` `/_ABD = (1)/(2)` m (arc APD ) ...(1)
`/_ACD = (1)/(2) ` m (arc APD ) Inscribed angle theorem ) …(2)
From (1) and (2), we get
`/_ABD ~= /_ACD `