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यदि `sin 3 theta=cos (theta-6^(@)),` यहाँ, `3 theta`व `(theta-6^(@))` न्यूनकोण है तब `theta` का मान ज्ञात कीजिए.

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यहाँ, `sin 3 theta=cs (theta-6^(@))`
`impliescos (90^(@)-3 theta)=cos (theta-6^(@))`
`impliescos (90^(@)-3theta)=cos (theta-6^(@))`
`implies90^(@)-3 theta=theta-6^(@)`
`implies4 theta =96^(@)impliestheta=24^(@)`

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