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`DeltaABC` में `angleB=90^(@)` तथा `AB=BC=5,` सेमी, तब `sin A` `tanC` के मान ज्ञात कीजिए.

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`DeltaABC` में `angleB=90^(@)` तथा `AB=BC=5,` सेमी, तब `sin A` `tanC` के मान ज्ञात कीजिए.
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यहाँ `AC=sqrt(AB^(2)+BC^(2))=sqrt(5^(2)+5^(2))=sqrt50 =5sqrt2`
अब `sin A=(BC)/(AC)=(5)/(5sqrt2)=(1)/(sqrt2)`
तथा `tan C=(AB)/(BC)=5/5=1`
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