
Let us consider a triangle ABC. Let O be the fixed point,

Position vector of the mid point P is vector OP = ½ vector (OB + OC) = ½ vector( b + c )
If G divides vector AP in the ratio 2 : 1
Then, the position vector of G =

The symmetry of this result show that , the point which divides the other two medians in the ratio 2 : 1 will also have the same position vector

Hence, the medians of a triangle are concurrent at G.