Question

In the figure find ∠APB,∠ABQ ; where O is the centre of the circle ∠OAP = 32° and  ∠OBP = 47°.

Answer 1

Join OP.

In OAP, OA = OP = Radius

∠OAP = ∠OPA = 32° 

In OPR, OB = OP = radius 

∠OBP = ∠OPB =47° 

∠APB = 32°+ 47°= 79° 

∠AQB = 180° – 79°= 10°