Question

In the figure O is the centre of the circle. Central angle of arc AXB is 60°, arc CYD is 80°. Then find all the angles of ΔAPD.

Answer 1

Central angle of arc AXB = 60° 

i.e., ∠AOB = 60°

i.e., ∠ADP = 30° 

Central angle of arc CYD = 80° 

i.e., ∠COD = 80° 

i e., ∠DPA = 40° 

i e., ∠APD = 180° – (30 + 40) = 110° 

Angles of = 30°, 40°, 110°