From the above figure, the position of green flag posted by Niharika is `M(2, (1)/(2)xx100)i.e., `
`M(2, 25)` and red flag posted by Preet is `N(8,(1)/(5)xx100)i.e., N(8, 20)`
Now, `MN=sqrt((8-2)^(2)+(20-25)^(2))=sqrt((6)^(2)+(-5)^(2))=sqrt(36+25)=sqrt(61)`
Hence, the distance between flags = `sqrt(61)` m
Let P be the position of the blue flag posted by Rashmi in the halfway of line segment MN.
`therefore" "P` is given by = `((x_(1)+x_(2))/(2), (y_(1)+y_(2))/(2))=((2+8)/(2), (25+20)/(2))=((10)/(2), (45)/(2))=(5, 22.5)`
Hence, the blue flag is on the fifth line at a distance 22.5 m above it.