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If the sum of the areas of two circles with radii `R_(1)` and `R_(2)` is equal to the area of a circle of radius R, then
A. `R_(1) + R_(2) = R`
B. `R_(1)^(2)+R_(2)^(2) = R^(2)`
C. `R_(1) + R_(2) lt R`
D. `R_(1)^(2) + R_(2)^(2) lt R^(2)`

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Best answer
Correct Answer - B
According to the given condition,
Area of circle = Area of first circle + Area of second circle
`:. piR^(2)= piR_(1)^(2) + piR_(2)^(2)`
`rArr R^(2)= R_(1)^(2) + R_(2)^(2)`

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