Let the length of each side of the cube be a unit. Since the cube is divided into two cuboidal object, so the length of the vuboidal object will be a unit, breadth a unit and height `a/2` unit.
Now, the total surface area of the cube `=6a^2` sq-units and the total surface area fo each cboidal object
`=2(axxa+axxa/2+a/2xxa)`sq - units =2 `(a^2+a^2/2+a^2/2)` sq - units
`=2((2a^2+a^2+a^2)/(2))` sq - units = 2 `((4a^2)/(2))` sq- units `=4a^2`sq - units
So, (the total surface area of the cube ) : (the total surface area of each cuboidal object) `= 6a^2 : 4a^2` = 3 : 2
Hence the required ratio = 3 : 2.
