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In the formula `bar(x)=a+h(sumf_(i)u_(i))/(sumf_(i))` for finding the mean of grouped frequency distribution `u_(i)` is equal to

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In the formula `bar(x)=a+h(sumf_(i)u_(i))/(sumf_(i))`
for finding the mean of grouped frequency distribution `u_(i)` is equal to
A. `(x_(i)+a)/(h)`
B. `h(x_(i)-a)`
C. `(x_(i)-a)/(h)`
D. `(a-x_(i))/(h)`
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Correct Answer - C
Given,`bar(x)=a+h bar(x)=a+h((sumf_(i)u_(i))/(sumf_(i)))`
Above formula is a step deviation formula,
`u_(i)=(x_(i)-a)/(h)`
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