a. Total number of balls in the first bag = 10 + 12 =22, Number of yellow balls = 12
Probability of getting a yellow ball = \(\frac{12}{22}=\frac{6}{11}\)
b. Total number of balls in the second bag = 15 + 7 = 22, Number of a yellow ball = 7
Probability of getting a yellow ball = \(\frac{7}{22}\)
c. Total number of balls = 22 + 22 = 44 Number of yellow balls = 12 + 7 = 19
Probability of getting a yellow ball = \(\frac{19}{44}\)
