Question

A bag contains 6 red balls, 8 green balls, and 8 white balls. One ball is drawn at random from the bag, find the probability of getting 

i. A white or green ball 

ii. Neither green ball nor a red ball.

Answer 1

Red balls = 6 

Green balls = 8 

White balls = 8 

Total number of balls = 6 + 8 + 8 = 22 

a. The probability of getting a white or green ball = 16/20 

b. The probability of getting neither green balls nor a red ball = 8/20