Question

a. How many two-digit natural numbers are there in all?

b. If we choose one number from the two digit numbers, what is the probability that the sum of digits of that number will be 10?

Answer 1

a. Number of two-digit natural numbers = 90

b. Numbers whose sum of digits will be 10 is 19, 28, 37, 46, 55, 64, 73, 82, 91

Probability that the sum of digits of that number will be 10 = \(\frac{9}{90}=\frac{1}{10}\)