a. Total outcomes
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6) ‘ (2,1), (2,2), (2,3), (2,4), (2,5), (2,6) . (3,1), (3,2), (3,3), (3,4), (3,5), (3,6) (4.1), (4,2), (4,3), (4,4), (4,5), (4,6) (5.1) , (5,2), (5,3), (5,4), (5,5), (5,6) (6.1), (6,2), (6,3), (6,4), (6,5), (6,6)
Total = 36
b. Sum of two numbers is to be 8 = 5 (2,6), (3,5), (4,4), (5,3), (6,2), Probability = 5/36
c. Probability of being same number =(1,1), (2,2), (3,3), (4,4), (5,5), (6,6),
Total = 6
Probability = \(\frac{6}{36}=\frac{1}{6}\)