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in Second Degree Equations by (30.9k points)
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An isosceles triangle has to be made like this

The height should be 2 meters less than the base. The area of the triangle should be 12 square meters. What should be the length of its sides?

1 Answer

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by (30.5k points)
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Best answer

Base = AB = x 

Height = CD = x – 2

Area = \(\frac{1}{2}\times x(x-2)=12\)

\(x^2-2x=24\)

\((x-1)^2=25\)

\(x-1=\pm 5\)

\(x-1=5,x=6\,;\,AC=BC\)

\(\sqrt{4^2+3^2}=5\)

Base = 6m, Height = 4m Edges = 5cm

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