Let the points of intersections of the lines x – y + 1 = 0, x – 2y + 3 = 0 and 2x – 5y + 11 = 0 are the mid points of the sides of a triangle ABC. - Sarthaks eConnect

Let the points of intersections of the lines x – y + 1 = 0, x – 2y + 3 = 0 and 2x – 5y + 11 = 0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is _______.

Let the points of intersections of the lines x – y + 1 = 0, x – 2y + 3 = 0 and 2x – 5y + 11 = 0 are the mid points of the sides of a triangle ABC.

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Find MCQs & Mock Test

Related questions

Categories