Question

Let us consider a curve, y = f(x) passing through the point (–2, 2) and the slope of the tangent to the curve at any point (x, f(x)) is given by f(x) + xf'(x) = x².

Then :

(1) x² + 2xf(x) – 12 = 0 

(2) x³ + xf(x) + 12 = 0 

(3) x³ – 3xf(x) – 4 = 0 

(4) x² + 2xf(x) + 4 = 0

Answer 1

Option : (3). x³ – 3xf(x) – 4 = 0