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in Mathematics by (30.6k points)

\(\displaystyle\sum_{k=0}^{20}\)(20Ck)2 is equal to :

∑(20Ck)2, k∈(0,20)

(1) 40C21

(2) 40C19

(3) 40C20

(4) 41C20

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1 Answer

+3 votes
by (30.7k points)

Option : (3). 40C20

∑(20Ck)2, k∈(0,20)

 \(\displaystyle\sum_{k=0}^{20}\)20Ck.20C20-k

sum of suffix is const. so summation will be 40C20.

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