Question

The sum of a number is 12 and sum of its reciprocal is 3/8 Find the numbers.

Answer 1

If we take numbers as 6 + x, 6 – x

\(\frac{1}{6+x}+\frac{1}{6-x}=\frac{3}{8}\)

12 x 8 = 3 (36 - x²),

96 = 108 - 3x²

3x² = 12x² = 4,

x - 2 or -2

Numbers = 6 + 2 = 8, 6 - 2 = 4