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`lim_(x->pi)((sin3x-3sinx)/((pi-x)^3))`

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`lim_(x->pi)((sin3x-3sinx)/((pi-x)^3))`
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Given limit `=lim_(xto pi)((3sinx-4sin^(3)x-3sinx))/((pi-x)^(3))`
`=lim_(xto pi)(-4sinx)/((pi-x)^(3))=lim_(thetato0)(-4sin^(3)(pi+theta))/((-theta)^(3))where (x-pi)=theta`
`=-4lim_(thetato0)((sintheta)/(theta))=(-4xx1)=-4.`
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