Correct Answer - B
The combined equation of the bisectors of the angles between the lines given by `ax^(2)+2hxy+by^(2)=0` is
`(x^(2)-y^(2))/(a-b)=(xy)/(h)rArr hx^(2)-(a-b)xy-hy^(2)=0" …(i)"`
It is given that `y=mx` is one of the lines given by this equation.
Therefore,
`h-(a-b)m-hm^(2)=0" "["Putting y = mx in (i)"]`
`rArr" "h(m^(2)-1)+m(a-b)=0`