Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
209 views
in Straight Lines by (70.6k points)
closed by
If the line `y = mx` bisects the angle between the lines `ax^2 + 2h xy + by^2 = 0` then ` m ` is a root of the quadratic equation
A. `h(m^(2)-1)+m(b-1)=0`
B. `h(m^(2)-1)+m(a-b)`
C. `h(m^(2)+1)+m(a-b)=0`
D. none of these

1 Answer

0 votes
by (71.2k points)
selected by
 
Best answer
Correct Answer - B
The combined equation of the bisectors of the angles between the lines given by `ax^(2)+2hxy+by^(2)=0` is
`(x^(2)-y^(2))/(a-b)=(xy)/(h)rArr hx^(2)-(a-b)xy-hy^(2)=0" …(i)"`
It is given that `y=mx` is one of the lines given by this equation.
Therefore,
`h-(a-b)m-hm^(2)=0" "["Putting y = mx in (i)"]`
`rArr" "h(m^(2)-1)+m(a-b)=0`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...